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A cricket ball of mass 0.5 kg strikes a bat normally with a velocity of "30 ms"^(-1) and rebounds with a velocity of "20 ms"^(-1) in the opposite direction, calculate the impulse of the force exerted by the ball on the bat. |
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Answer» Solution :`"Impulse"="CHANGE in MOMENTUM"` `= m U-(-m V)` `=m(u+v)=0.5(30+20)=25Ns` |
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