1.

A cricket ball of mass 0.5 kg strikes a bat normally with a velocity of "30 ms"^(-1) and rebounds with a velocity of "20 ms"^(-1) in the opposite direction, calculate the impulse of the force exerted by the ball on the bat.

Answer»

Solution :`"Impulse"="CHANGE in MOMENTUM"`
`= m U-(-m V)`
`=m(u+v)=0.5(30+20)=25Ns`


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