A crowbar 2 m long is pivoted about a point 10 cm from its tip. (i) Calculate the mechanical advantage of the crowbar. (ii) What is the least force which must be applied at the other end to displace a load of 100 kgf?

A crowbar 2 m long is pivoted about a point 10 cm from its tip. (i) C

1.	A crowbar 2 m long is pivoted about a point 10 cm from its tip. (i) Calculate the mechanical advantage of the crowbar. (ii) What is the least force which must be applied at the other end to displace a load of 100 kgf?
Answer» Solution :Given: L=100kgf, since load is at tip which is at distance 10 cm from the fulcrum, so load ARM=10 cm, Total length of crowbar=2 m=200 cm Effort arm=200-10=190cm, E=? (i) MECHANICAL ADVANTAGE=`("effort arm")/("load arm")=(190)/(10)=19` (ii) Taking moments about the pivot (fulcrum), `Exx190=100xx10` `E=(100xx10)/(190)=5*26kgf`.