InterviewSolution
Saved Bookmarks
| 1. |
A current carrying conductro of certain length, kept perpendicular to the magnetic field experiences a force F. What will be the force if the current is increased four times, lengthis halved and magnetic field is tripled? |
|
Answer» Solution :`F=1LB=(4I)xx(L//2)xx(3B)=6F` THEREFORE, the forces inreases SIX times |
|