A current of 9.65 A is passed through three different electrolytes NaCl, AgNO_(3) and CuSO_(4) for 30 min separately. Calculate the ratio of the metals deposited at the respective electrodes. Also find out the weights of various metals deposited at the respective electrodes

A current of 9.65 A is passed through three different electrolytes NaC

1.	A current of 9.65 A is passed through three different electrolytes NaCl, AgNO_(3) and CuSO_(4) for 30 min separately. Calculate the ratio of the metals deposited at the respective electrodes. Also find out the weights of various metals deposited at the respective electrodes
Answer» Solution :Quantity of electricity passed through the electrolyte = current strength `xx` time of flow = `9.65 xx 30 xx 60` coulombs `m_(Na) : m_(AG) : m_(Cu) = E_(Na) : E_(Ag) : E_(Cu)` `E_(Na) = (23)/(1) = 23 "" (Na^(+) + E^(-) rarr Na)` `E_(Ag) = (108)/(1) = 108 (Ag^(+) + e^(-) rarr Ag)` `E_(Cu) = (63.5)/(2) 31.75 "" (Cu^(+2) + 2e^(-) rarr Cu)` `m_(Na) : m_(Ag) : m_(Cu) = 23 : 108 : 31.75` Weight of sodium deposited `= (23 xx 9.65 xx 30 xx 60)/(96500) = 4.14g` Weight of silver deposite `= (108 xx 9.65 xx 30 xx 60)/(96500) = 19.44 G` Weight of copper deposited `= (31.75 xx 9.65 xx 30 xx 60)/(96500) = 5.715g`