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A current waveform is of the shape of a right angled triangle with period of t = 1 sec. Given a resistance R = 1 Ω. The average power is __________(a) 1 W(b) 0.5 W(c) 0.333 W(d) 0.111 WI had been asked this question during an online interview.I would like to ask this question from Advanced Problems on Network Theorems topic in chapter Useful Theorems in Circuit Analysis of Network Theory

Answer»

Right choice is (d) 0.111 W

To explain: We KNOW that RMS current is,

I = 1 \( \int_0^1 (1T)^2\,dt\)

= \( \int_0^1 t^2\,dt\)

= \(\frac{1}{3}\) A

Now, power P = I^2R

= \(\frac{1}{9}\) X 1

= 0.111 W.



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