1.

a. Define ocal length of a divergent lens. b. A divergetn lens of focal length 30 cm forms the image of an object of size 6 cm on the same side as the object at a distance of 15 cm from its optical centre. Use lens formula to determine the distance of the object the lens and the size of the image formed.

Answer»

SOLUTION :a. The distance between the principal focus and the optical CENTRES of the concave lens or diverging lens is called the FOCAL length of a diverging lens.
b. `f=-30cm`
`h=6cm`
`v=15cm, u=?,h=?`

Lens formula:
`1/v-1/u=1/f` or `(-1)/u=1/f-1/v`
`(-1)/15-1/u=(-1)/30` or `(-1)/u=(-1)/30-((-1)/15)`
`(-1)/u=(-1)/30+1/15`
`(-1)/u=(-15+30)/450`
`(-1)/u=1/30`
`=u=30`
`u=-30cm`
The object distance is -30 cm.
`m=v/u=(h^(1))/h`
`(+15)/(+30)=(h^(1))/6` or `6/2=h^(1)`
`h^(1)=3 cm`
The height of the image is 3 cm.


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