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a. Define ocal length of a divergent lens. b. A divergetn lens of focal length 30 cm forms the image of an object of size 6 cm on the same side as the object at a distance of 15 cm from its optical centre. Use lens formula to determine the distance of the object the lens and the size of the image formed. |
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Answer» SOLUTION :a. The distance between the principal focus and the optical CENTRES of the concave lens or diverging lens is called the FOCAL length of a diverging lens. b. `f=-30cm` `h=6cm` `v=15cm, u=?,h=?` ![]() Lens formula: `1/v-1/u=1/f` or `(-1)/u=1/f-1/v` `(-1)/15-1/u=(-1)/30` or `(-1)/u=(-1)/30-((-1)/15)` `(-1)/u=(-1)/30+1/15` `(-1)/u=(-15+30)/450` `(-1)/u=1/30` `=u=30` `u=-30cm` The object distance is -30 cm. `m=v/u=(h^(1))/h` `(+15)/(+30)=(h^(1))/6` or `6/2=h^(1)` `h^(1)=3 cm` The height of the image is 3 cm. |
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