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A dishonest milkman fills up his bucket, which is only 4/7th full of milk, with water. He again removes 3 litres of this mixture from the bucket and adds an equal quantity of water. If milk is now 40% of the mixture, then what is the capacity of the bucket?1). 25 litres2). 40 litres3). 15 litres4). 10 litres |
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Answer» Let the capacity of bucket be X litres ⇒ Quantity of MILK = (4/7)X ⇒ Quantity of water = 1 – (4/7)X = (3/7)X ⇒ If 3 litres mixture is REMOVED, REMAINING mixture = X – 3 ⇒ Now quantity of milk = (4/7) × (X – 3) ⇒ If 3 litres water is added, quantity of water = (3/7) × (X – 3) + 3 ⇒ (4/7) × (X – 3) = 40% of X ⇒ (4/7)X – 12/7 = (40/100)X ⇒ {(4/7) – (40/100)}X = 12/7 ∴ X = 10 litres |
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