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A does 50% of a work in 12 days. He then calls in B and they together finish the remaining work in 8 days. How long B alone would take to complete the whole work?1). 12 days2). 24 days3). 36 days4). 48 days |
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Answer» A does 50% of a WORK in 12 days. So, the part of work DONE A in 1 day = (1/2)/12 = 1/24 Remaining part of work = 1 – ½ = ½ The part of work done by A in 8 days = 8 × (1/24) = 1/3 So, B does (1/2) – (1/3) = 1/6 part of the work in 8 days. So, the part of work done by B in 1 day = (1/6)/8 = 1/48 ∴ B would ALONE COMPLETE the work in 48 days. |
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