1.

A does half as much work as B is one sixth of the time. If together they take 10 days to complete a work, how much time shall A alone take to do it?1). 70 days2). 30 days3). 14 days4). 50 days

Answer»

Given,

⇒ A × 1/6 = B × 1/2

⇒ A = 3B

⇒ $(\frac{A}{B} = \frac{3}{1})$

∴ A’s efficiency = 3 unit / day.

& B’s efficiency = 1 unit / day.

According to Qs.

(A + B) Complete in 10 day

TOTAL Work = (3 + 1) × 10

= 4 × 10 = 40

∴ Time taken by $(A = \frac{{40}}{{13}})$

= 13.33 DAYS = 14 Days.



Discussion

No Comment Found

Related InterviewSolutions