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A does half as much work as B is one sixth of the time. If together they take 10 days to complete a work, how much time shall A alone take to do it?1). 70 days2). 30 days3). 14 days4). 50 days |
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Answer» Given, ⇒ A × 1/6 = B × 1/2 ⇒ A = 3B ⇒ $(\frac{A}{B} = \frac{3}{1})$ ∴ A’s efficiency = 3 unit / day. & B’s efficiency = 1 unit / day. According to Qs. (A + B) Complete in 10 day ∴ TOTAL Work = (3 + 1) × 10 = 4 × 10 = 40 ∴ Time taken by $(A = \frac{{40}}{{13}})$ = 13.33 DAYS = 14 Days. |
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