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A domesticcircuithas a line of 5A ratting. Howmany lamps of ratting 40w, 220 V can berun simultaneously on this line safely ?

Answer»

Solution :The currentratingof one lamp .
` I = (P)/(V) = (40W)/(220 V) =(2)/(11) A`
Thus, CURRENT of `(2)/(11)A` is requiredby one lamp to glow completely.
Now , the currentrating (i.e., Maximum currentin the line )= 5A.
`therefore`The numberof lamps that can be RUN simultaeouslyon thisline safely .
` = ("current rating of the line")/("current rating of one lamp")`
`= (5A)/((2)/(11)A)`
` = (55)/(2)`
` = 27.5`
`~~27`


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