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(a) Draw a ray diagram to show the formation of image of an object placed between infinity and optical centre of a concave lens. (b) A concave lens of focal length 15 cm forms an image 10 cm from the lens. Calculate (i) the object distance, (ii) the nature and magnification of the image formed. |
Answer» Solution :(a) A ray diagram showing the FORMATION of image of an object placed between infinity and optical CENTRE of a concave lens is shown below. (b) Here f = - 15 cm, v = - 10 cm (i) From lens FORMULA `(1)/(v) - (1)/(u) = (1)/(f)`, we have `(1)/(u) = (1)/(v) - (1)/(f) = (1)/((-10)) - (1)/((-15)) = - (1)/(10) + (1)/(15) = - (1)/(30)` `rArr""u = - 30` cm THUS, the object is placed at a distance of 30 cm from the concave lens and the image is a virtual image. (ii) Magnification `m = (v)/(u) = ((-10))/((-30)) = (1)/(3) = 0.33` |
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