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A drum full of rice weight \(40\frac{1}{6}\)kg. If the empty drum weight \(13\frac{3}{4}\)kg. Find the weight of rice in the drum. |
Answer» Weight of drum full of rice = \(40 \frac{1}{6}\) kg Weight of empty drum \(=13\frac{3}{4}\)kg Weight of rice Weight of drum full of rice - Weight of empty drum \(=40\frac{1}{6}\)kg - \(13\frac{3}{4}\)kg \(=\frac{241}{6}\)kg - \(\frac{55}{4}\)kg \(=\frac{482-165}{12}\)kg \(=\frac{317}{12}\)kg \(=26\frac{5}{12}\)kg Hence, Weight of rice \(=26\frac{5}{12}\)kg |
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