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A dye absorbs a photon of wavelength `lambda` and re`-` emits the same energy into two phorons of wavelengths `lambda_(1)` and `lambda_(2)` respectively. The wavelength `lambda` is related with `lambda_(1)` and `lambda_(2)` as `:`A. `lambda=(lambda_(1)+lambda_(2))/(lambda_(1)lambda_(2))`B. `lambda=(lambda_(1)lambda_(2))/(lambda_(1)+lambda_(2))`C. `lambda=(lambda_(1)^(2)lambda_(2)^(2))/(lambda_(1)+lambda_(2))`D. `lambda=(lambda_(1)lambda_(2))/((lambda_(1)+lambda_(2))^(2))` |
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Answer» Correct Answer - B `E=E_(1)+E_(2),(hc)/(lambda)=(hc)/(lambda_(1))+(hc)/(lambda_(2))" "rArr" "(hc)/(lambda)=hc((lambda_(2)+lambda_(1))/(lambda_(1)lambda_(2))),lambda=(lambda_(1)lambda_(2))/(lambda_(1)+lambda_(2))` |
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