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A force F = x + 1 N acts on a particle in x direction. What is the work done from x = 2m to 5 m?(a) 10.5 J(b) 14.5 J(c) 13.5 J(d) 0.5 JThis question was addressed to me during an internship interview.My question is taken from Work Done by a Variable Force in section Work, Energy and Power of Physics – Class 11

Answer»

Correct option is (c) 13.5 J

The explanation: Work DONE is given by W = \(\int_{x1}^{X2}\)F * DX. So, W = \(\int_{2}^{5}\)(x + 1) * dx = [(5^2/2 + 5) – (2^2/2+2)] = 13.5.



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