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A force is applied on a cube of side 3m. Another force, double the magnitude of the previous force is applied on a cube of 1m. What is the ratio of pressure on the first cube (P) to the pressure on the second cube (P’)?(a) 1/9(b) 18(c) 1/18(d) 1/2This question was addressed to me during an interview for a job.The question is from Fluids Mechanical Properties Pressure topic in section Mechanical Properties of Fluids of Physics – Class 11 |
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Answer» CORRECT OPTION is (C) 1/18 The EXPLANATION: P = F/3^2 P = F/9 P’ = 2F/1^2 P’ = 2F/1 P/P’ = (F/9)/(2F/1) = 1/18. |
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