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A force is applied on a cube of side 3m. Another force, double the magnitude of the previous force is applied on a cube of 1m. What is the ratio of pressure on the first cube (P) to the pressure on the second cube (P’)?(a) 1/9(b) 18(c) 1/18(d) 1/2This question was addressed to me during an interview for a job.The question is from Fluids Mechanical Properties Pressure topic in section Mechanical Properties of Fluids of Physics – Class 11

Answer» CORRECT OPTION is (C) 1/18

The EXPLANATION: P = F/3^2

P = F/9

P’ = 2F/1^2

P’ = 2F/1

P/P’ = (F/9)/(2F/1)

 = 1/18.


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