1.

A force of 98 N is just required to move a mass of 45 kg on a rough horizontal surface. Find the coefficient of friction and angle of friction ?

Answer»

Solution :F=98N, `R=45 XX 9.8 =441N`
`mu^(2)=(F')/(R)=0.22`
ANGLE of friction `theta=tan^(-1) mu=tan^(-1)0.22=12^(@)24'`


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