A Fuel Dealer Mixes Two Brands Of Fuel Which Cost In The Ratio 2:3. A

1.	A Fuel Dealer Mixes Two Brands Of Fuel Which Cost In The Ratio 2:3. A Solution Containing 30% Brand A And Remaining Brand B Yields Profit Of 10% When Sold At Rs 297. What Is Cost Of Brand B?
Answer» Let quantity of solution sold be 1 litre When the solution is sold for 297, the profit percent = 10% HENCE CP of of solution = SP × 100/(100+P%) ⇒CP = 297 × 100/(100+10) ⇒CP = 270 RATIO of quantities of brand A and brand B is 3:7 Let their COSTS be 2C and 3c. ⇒ 0.3×2c + 0.7×3c = 270 ⇒ 2.7c = 270 ⇒ c = 100 Hence cost of Brand B = 3c = 300 Let quantity of solution sold be 1 litre When the solution is sold for 297, the profit percent = 10% Hence CP of of solution = SP × 100/(100+P%) ⇒CP = 297 × 100/(100+10) ⇒CP = 270 Ratio of quantities of brand A and brand B is 3:7 Let their costs be 2c and 3c. ⇒ 0.3×2c + 0.7×3c = 270 ⇒ 2.7c = 270 ⇒ c = 100 Hence cost of Brand B = 3c = 300

A Fuel Dealer Mixes Two Brands Of Fuel Which Cost In The Ratio 2:3. A Solution Containing 30% Brand A And Remaining Brand B Yields Profit Of 10% When Sold At Rs 297. What Is Cost Of Brand B?

Answer»

Let quantity of solution sold be 1 litre

When the solution is sold for 297, the profit percent = 10%

HENCE CP of of solution = SP × 100/(100+P%)

⇒CP = 297 × 100/(100+10)

⇒CP = 270

RATIO of quantities of brand A and brand B is 3:7

Let their COSTS be 2C and 3c.

⇒ 0.3×2c + 0.7×3c = 270

⇒ 2.7c = 270

⇒ c = 100

Hence cost of Brand B = 3c = 300