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A gas absorbs a photon fo ` 355nm` and emits at two wavelengths . If one fo the emission is at ` 6 80` nm , the other si at :A. ` n= 4 , l=1`B. ` n = 4, l=0`C. ` n = 3, 1=2`D. `n= 3, l=1` |
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Answer» Correct Answer - C ` E = hv = hc //lambda ` ` E =E_1 + E_2` or `( hc)/(lambda ) = (hc)/(lambda _1) + (hc)/(lambda _2)` ` rArr lambda = 1/lambda = 1/(lambda _1) +1/(lambda _2) rArr 1/( 355) = 1/(680) + 1/(lambda _2)` `:. lambda _2 = ( 355 xx 680)/( 680 -355) = 742.769 nm ~~ 743 nm`. |
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