A gas with molecular formula C_(n)H_(2n + 2) diffuses through a porous plug at a rate 1//6th of the rate of diffusion of hydrogen gas under similar condtition. The formula of the gas is:

A gas with molecular formula C_(n)H_(2n + 2) diffuses through a porous

1.	A gas with molecular formula C_(n)H_(2n + 2) diffuses through a porous plug at a rate 1//6th of the rate of diffusion of hydrogen gas under similar condtition. The formula of the gas is:
Answer» SOLUTION :Let the molecular weight of the hydrocarbon be `M_(X)` and its rate of diffusion be `r_(x)` `r_(H_(2))/r_(x) =SQRT(M_(x)/M_(H_(2))), r_(x) = 1//6r_(H_(2))` `:. r_(H_(2))/r_(x)=6=sqrt(M_(x)/2)` ` RARR 36 XX 2 = M_(x)` ` rArr M_(x) = 72` Molecular weight of thehydrocarbon is 72. Let thenumber of carbon atoms present in one molecule of the hydrocarbon be be m. `:' ` the hydrocarbon is saturated, the number of hydrogen atoms present in that hydrocarbon molecule is 2 m + 2 `:. (12 xxm) +2 m + 2 = 72` ` rArr 14 m +2 = 72 rArr m = 5` `:.` Molecular formula of the hydrocarbon is `C_(5)H_(12)`.