1.

A geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of the earth. What is the potential due to earth's gravity at the site of the satellite ? Mass of the earth= 6xx10^(24)kg and radius =6400 km.

Answer»

Solution :U= Potential at height `h= -(GM)/(R+h)`
`U=(6.67xx10^(-11)xx6xx10^(24))/(6.4xx10^(6)+36xx10^(6))= -9.44xx10^(6) J"/"KG`.


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