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InterviewSolution
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A hare sees a dog 200 m away from her and scuds off in the opposite direction at a speed of 24 km/hr. Two minutes later, the dog perceives her and gives chase at a speed of 32 km/hr. How soon will the dog overtake the hare and what is the distance from the spot from where the hare took flight? (a) 8 min 2 km (b) \(7\frac12\) min, 2 km (c) \(7\frac12\) min, 3 km (d) \(7\frac12\) min, 1 km |
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Answer» (c) \(7\frac12\) min, 3km Distance covered by hare in 2 min \(=\frac{24}{60}\times\)1000 x 2 = 800 m Now to overtake the hare, the dog has to cover a distance of (800 + 200) = 1000 m with a relative speed = (32 – 24) km/hr = 8 km/hr ∴ Time taken = \(\frac18\) hrs = \(\bigg(\frac18\times60\bigg)\) min = \(7\frac12\) min ∴ Distance travelled by hare in \(\frac18\) hrs = \(\bigg(\frac18\times24\bigg)\) km = 3km. |
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