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    				| 1. | Two trains travel in the same direction at 60 km/hr and 96 km/hr. If the faster train passes a man in the slower train in 20 seconds, then the length of the faster train is (a) 100 m (b) 125 m (c) 150 m (d) 200 m | 
| Answer» (d) 200 m Relative speed = (96 – 60) km/hr = 36 km/hr =\(\bigg(36\times\frac{5}{18}\bigg)\) m/s = 10 m/sec As we know D = s × t ∴ Length of faster train = 10 × 20 = 200 m. | |