1.

A thief seeing a policeman from a distance of 200 metres, starts running with a speed of 8 km/hr. The policeman gives chase immediately with a speed of 9 km/hr and the thief is caught. What is the distance run by the thief?

Answer»

Relative speed of the policeman with respect to that of thief = (9 – 8) km/hr = \(1\times\frac{5}{18}\) m/sec

⇒ Time taken by the policeman to catch the thief = \(\frac{200}{\frac{5}{18}}\) sec = 720 seconds 

∴ The distance run by the thief = \(\bigg(8\times\frac{5}{18}\times720\bigg)\) metres = 1600 metres



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