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A heavy nucleus (mass number = A) splits into two new nuclei, whose mass numbers are in the ratio 3:2 . The ratio of radii of these new nuclei isA. `3:2`B. `2:3`C. `3^(1//3):2^(1//3)`D. `2^(1//3) : 3^(1//3)` |
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Answer» Correct Answer - C `r_(1)/r_(2) = (r_(0) xx (A_(1))^(1//3))/(r_(0) xx (A_(2))^(1//3))=(A_(1)/A_(2))^(1//3)={((3/5 xx A))/((2/5 x A))}^(1/3)=3^(1//3)/(2^(1//3)` |
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