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If reactor takes 30 day to consume 4 kg of fuel and each fission gives 185 MeV of usable energy , then calculate the power output.A. `2.75 xx 10^(10)` WB. `0.012 xx 10^(10)` WC. `3.5 xx 10^(10)` WD. ` 7.63 xx 10^(10)` W |
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Answer» Correct Answer - B 235 amu of uranium gives energy of 185 MeV . `185 / 235 xx 1.6 xx 10^(-13)` J also, 1 amu =`1.66 xx 10^(-27)` kg so, energy by 1 amu or `1.66 xx 10^(-27)`1kg of = `(185 xx 1.6 xx 10^(-13))/ (235)` Energy released by 4 kg of `implies` W = `(185 xx 1.6 xx 10^(-13) xx 4) / (1.66 xx 10^(-27)` xx 235)` = `(3.035 xx 10^(14))` J Power of reactor = `(3.035 xx 10^(14))/(30 xx 24 xx 60 xx 60)` = `(0.012 xx 10^(10))` W |
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