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The radius of `Na^(23)` nucleus isA. `3.125 xx 10^(-15) m`B. `23 xx 10^(-15) m`C. `11 xx 10^(-15) m `D. `1.1 xx 10^(-15) m` |
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Answer» Correct Answer - A R = `R_(0)``A^(1/3)` = `1.1 xx 10 ^(-15) xx (23)^(1/3)` = `3.125 xx 10^(-15)`m |
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