A heavy truck and bike are moving withthe same kinetic energy . If the mass of the truck is four timesthat of the bike , then calculate the ratio of theirmomenta . (Ratioof momenta = 1:2)

A heavy truck and bike are moving withthe same kinetic energy . If the

1.	A heavy truck and bike are moving withthe same kinetic energy . If the mass of the truck is four timesthat of the bike , then calculate the ratio of theirmomenta . (Ratioof momenta = 1:2)
Answer» Solution :(i) GIVEN: Let `m_(b),m_(1)` are the masses of truck and BIKE, `m_(1)=4m_(b)`. . . (1) Here kinetic ENERGIES of both truck and bike are same `(1)/(2)m_(1)v_(1)^(2)=(1)/(2)m_(b)v_(b)^(2)`. . (2) `(1)/(2)xx4m_(b)vt^(2)=(1)/(2)m_b v_(b)^(2)` `v_(t)^(2)=v_(b)^2` `v_(t)^(2)=(1)/(4)v_(b)^(2)` `v_(t)=(1)/(2)v_(b)` To find ratio of the momenta, (i.e) `m_(1):v_(1):m_(b)v_(b)` `(P_(truck))/(P_(bike))=(m_(t)v_(t))/(m_(b)v_(b))` `=4XX(1)/(2)=(2)/(1)=2:1` (or) `(P_(bike))/(P_(truck))=(1)/(2)=1:2` (ii) `v_(T)=(v_(o)+0.16T)` `T=46^(@)C,v_(o)=331ms^(-1)` `v_(T)=331+(0.61xx46)` `=331+28.06` `v_(T)=359.06ms^(-1)`. `v_(T)=(v_(o)+0.16T)` `T=46^(@)C,v_(o)=331ms^(-1)` `v_(T)=331+(0.61xx46)` `=331+28.06` `v_(T)=359.06ms^(-1)`