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A hemispheric dome of radius 3.5m is to be painted at a rate of ₹600/m^2. What is the cost of painting it? (Take π = \(\frac{22}{7}\))(a) ₹46200(b) ₹45000(c) ₹47260(d) ₹48375The question was asked in homework.This key question is from Surface Area of a Sphere in division Surface Areas and Volumes of Mathematics – Class 9 |
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Answer» RIGHT answer is (a) ₹46200 Easy explanation: We know that CURVED surface are of a hemisphere = 2πr^2 = 2 * \(\frac{22}{7}\) * (3.5)^2 = 77m^2 Now, the cost of painting 1m^2 of area = ₹600 Then, the cost of painting 77m^2 of area = 77 * 600 = ₹46200. |
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