A hiker stands on the edge of a cliff 490 m above the ground and throw – InterviewSolution

InterviewSolution

1.	A hiker stands on the edge of a cliff 490 m above the ground and throwns a stone horiozontally with an initial speed of 15ms^(-1) neglecting air resistance.The time taken by the stone to reach the ground in seconds is (g=9.8ms^(2))
Answer» Solution :time = 10 seconds `V=SQRT(V_(X)^(2)+V_(y)^(2))=sqrt(15^(2)-98^(2))=99.1m//s^(-1)`.

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