InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A human body required the 0.01 M activity of radioactive substance after 24 h. Half life of radioactive substance is 6h. Then injection of maximum activity of radioactie substance that can be injected will beA. 0.08B. 0.04C. 0.16D. 0.32 |
|
Answer» Correct Answer - C Remaining activity =0.01 M after 24 h Remaining activity =Initial activity `xx(1/2)^(n)` used half life time (n)=`("Total time")/(t_(1//2))=(24)/(6)=4` So, 0.01=Initial activity `xx(1/2)^(4)` Initial activity =`0.01xx16=0=0.16` |
|