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A hydraulic system is used to lift a 2000 kg vehicle in an auto garage. If the vehicle sits on a piston of area 0.5 m^(2) ,m, and a force is applied to a piston of area 0.03m^(2) , what is the minimum force that must be applied to lift the vehicle?Given: Area covered by the vehicle on the piston A_(1) = 0.5 m^(2) Weight of the vehicle , F_(1) = 2000 kg xx 9.8 m s^(-2) Area on which force F_(2) is aplied , A_(2) = 0.03 m^(2) |
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Answer» Solution :`P_(1) = P_(2) , F_(1)/A_(1) = F_(2)/A_(2) " and " F_(2) = F_(1)/A_(1) A_(2) ` , ` F_(2) = (2000 XX 9.8) (0.03)/(0.5) = 1176 ` N |
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