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A hydrogen atom in its ground state is irradiated by light of wavelength `970Å` Taking `hc//e = 1.237 xx 10^(-6)`eV m and the ground state energy of hydrogen atom as ` - 13.6 eV` the number of lines present in the emmission spectrum is |
Answer» Correct Answer - 6 Absorbed quantum energy in `(eV)=(hc)/(elamda)` `=(1.237xx10^(-6))/(970xx10^(-10))` `=12.75eV` Energy of nth shell `=-13.6+12.75` `=0.85`eV We know `E_(n)=(E_(1))/(n_(2))` `thereforen^(2)=(E_(1))/(E_(n))=(-13.6)/(-0.85)=16` i.e., `n=4` Number of spectral emission lines `=(n(n-1))/(2)=(4xx3)/(2)=6` |
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