A hydrogen like atom (atomic number Z) is in a higher excited satte of quantum number n .This excited atom can make a transition to the first excited state by succesively emitting two photon of energies `10.20 eV` and `17.00 eV` .Alternatively, the atom from the same excited state can make a transition to the second excited state by successively emitting twio photon of energy `4.25 ev` and `5.95 eV` Determine the followings: The excited sate (n) of the atom isA. 4B. 6C. 8D. 3

A hydrogen like atom (atomic number Z) is in a higher excited satte of

1.	A hydrogen like atom (atomic number Z) is in a higher excited satte of quantum number n .This excited atom can make a transition to the first excited state by succesively emitting two photon of energies `10.20 eV` and `17.00 eV` .Alternatively, the atom from the same excited state can make a transition to the second excited state by successively emitting twio photon of energy `4.25 ev` and `5.95 eV` Determine the followings: The excited sate (n) of the atom isA. 4B. 6C. 8D. 3
Answer» Correct Answer - B `n= 6` `n rarr 2: Delta E = 10.2 + 17 = 27.2 eV` `n rarr 3: Delta E = 4.25 + 5.95 = 10.2 eV` `{:(implies 27.2 = 13.6 Z^(2)(1/(2^(2))-1/(n^(2)))),(and 10.2 =13.6Z^(2)(1/(3^(2))-1/(n^(2)))):}} Rightarrow `Z = 3` and ` n =- 6`

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