InterviewSolution
Saved Bookmarks
| 1. |
A is 50% as efficient as B.C. does half of the work done by A and B together. If C alone does the work in 20 days, then A, B and C together can do the work in1). 52/3 days2). 62/3 days3). 6 days4). 7 days |
|
Answer» ⇒ Let the TIME taken by B to complete the work be x days ⇒ B’s one-day work = 1/x ⇒ Time taken by A to complete the work be 2x days ⇒ A’s one-day work = 1/2x ⇒ Work done by C in 1 day = (1/2) × (1/x + 1/2x) ⇒ Work done by C in 1 day = 3/4x ⇒ given C ALONE finish the work in 20 days ⇒ 3/4x = 1/20 ⇒ x = 15 ⇒ Work done by (A + B + C) for 1 day = (1/x + 1/2x + 3/4x) ⇒ Work done by (A + B + C) for 1 day = 1/30 + 1/15 + 1/20 = 9/60 = 3/20 ∴ REQD. time = 6 (2/3) days |
|