1.

A is 50% as efficient as B.C. does half of the work done by A and B together. If C alone does the work in 20 days, then A, B and C together can do the work in1). 52/3 days2). 62/3 days3). 6 days4). 7 days

Answer»

⇒ Let the TIME taken by B to complete the work be x days

⇒ B’s one-day work = 1/x

⇒ Time taken by A to complete the work be 2x days

⇒ A’s one-day work = 1/2x

⇒ Work done by C in 1 day = (1/2) × (1/x + 1/2x)

⇒ Work done by C in 1 day = 3/4x

⇒ given C ALONE finish the work in 20 days

⇒ 3/4x = 1/20

⇒ x = 15

⇒ Work done by (A + B + C) for 1 day = (1/x + 1/2x + 3/4x)

⇒ Work done by (A + B + C) for 1 day = 1/30 + 1/15 + 1/20 = 9/60 = 3/20

REQD. time = 6 (2/3) days



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