1.

A lift carries a maximum weight of 2400 N to a height of 10 m with a constant speed 2ms^(-1). Find out the power and the work done.

Answer»


Solution :Here, weight = force = `2400 N, h=10M,` speed = `2MS^(-1)`
Work done = `Fs=Fh=2400 Nxx10m`
`=24000J`
Speed = `("Distance")/("Time")`
`THEREFORE` Time = `("Distance")/("Speed")=(10m)/(2ms^(-1))=5s`
Power = `("Work")/("Time")=(24000J)/(5s)=4800W`


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