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A lift carries a maximum weight of 2400 N to a height of 10 m with a constant speed 2ms^(-1). Find out the power and the work done. |
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Answer» Work done = `Fs=Fh=2400 Nxx10m` `=24000J` Speed = `("Distance")/("Time")` `THEREFORE` Time = `("Distance")/("Speed")=(10m)/(2ms^(-1))=5s` Power = `("Work")/("Time")=(24000J)/(5s)=4800W` |
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