1.

A light ray is incident at an angle of 60^(@) at the interface of Medium X and medium Y air - water interface. If the angle of refraction is 30^(@).(i) Draw a diagram to represent the same.(ii) Find the refractive index of the Y with respect to medium X.(iii) If medium Y has a refractive index equal to 4/3, will the angle of refraction increase or decrease ?

Answer»

Solution :(i)
(ii) `mu_(yx)=(sin i)/(sin r)=(sin 60^(@))/(sin 30^(@))=((sqrt(3))/(2))/((1)/(2))=(sqrt(3))/(2)xx(2)/(1)=sqrt(3)=1.73`
(iii) If medium Y is replaced with a medium of refractive index 4/3 (= 1.33), then medium Y is optically rarer than the medium with refractive index = 1.73, the ANGLE of REFRACTION will be more than `30^(@)`.


Discussion

No Comment Found