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A light source of wavelength `lambda` illuminates a metal and ejects photo-electrons with `(K.E.)_(max) =1.eV` Another light source of wavelength `(lambda)/(3)`, ejects photo-electrons from same metal with `(K.E.)_(max) = 4eV` Find the value of work function?A. `1eV`B. `2eV`C. `0.5eV`D. `1.5eV` |
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Answer» Correct Answer - C `(hc)/(lambda) = phi +KE` |
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