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A load of 600 kgwt is raised over an inclined plane as shown in the following figure. How much force forming a couple should act on the pulley so that the load is just raised? |
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Answer» Solution :(i) Use the definition of mechanical advantage and principle of moments. (ii) Calculate the effort (E) required to pull the load, using E = mg ` SIN theta`. (iii) Part of the total FORCE requiredto pull the load is PROVIDED by 100 kgwt. (IV) Calculate the remaining force by ` E - (100 xx 10) N = F_(1)`. (v) `F_(1)xxR` forms anti-clockwise moment on the pulley, where R = radius of the pulley. (vi) Let `F_(2)` be theforce forming a couple so that the load is just raised. (vii) Calculate `F_(2)` using : `F_(1)xx R=F_(2)xx2(R)`. (viii) 1000 N. |
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