A man in a lift feels an apparent weight 'W' when the lift is moving up with a uniform dur to gravity . If the same man was in the same lift now moving down with a uniform acceleration that is 1/2 of the accel- eration due to gravity , then what is his apparent weight ?

A man in a lift feels an apparent weight 'W' when the lift is moving u

1.	A man in a lift feels an apparent weight 'W' when the lift is moving up with a uniform dur to gravity . If the same man was in the same lift now moving down with a uniform acceleration that is 1/2 of the accel- eration due to gravity , then what is his apparent weight ?
Answer» SOLUTION :Case (i) : When lift is moving upwards : Apparent WEIGHT of the man = W Acceleration , a = `g//3` Apparent weight of the man when the lift is moving upwards is, `W=m(a+g)=m((g)/(3)+g)` `= (4)/(3)mg=(4)/(3)N"" [becauseN=mg` `rArrN=(3)/(4)W` Case (ii) : When lift is moving downwards : Let W ' be the apparent weight of the man Acceleration , a = g / 2 Apparent weight of the man when the lift is moving downwards is , `W'=m(g-a)=m(g-g//2)` `=(1)/(2)mg=(N)/(2) [becauseN = mg] ` `=(1)/(2)((3)/(4)W)=(3)/(8)W`