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A man opens a nut by applying a force of 150 N by using a lever handle of length 0*4m. What should be the length of the handle if he wants to open it by applying a force of 60 N? |
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Answer» Solution :Given, when effort=150 N, effort arm=`0*4m`. when effort=60N, effort arm=? LOAD and load arm REMAINS the same in both CASES. `therefore 150xx0*4=60xx`effort arm or Effort arm (i.e., length of length) `=(150xx0*4)/(60)=1m`. |
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