1.

A man standing at a point on the line joining the feet of two cliffs fires a bullet . If he hears the 1^(st) echo after 4 seconds and the next after 6 seconds , then what is the distance between the two cliffs ? (Take the velocity of sound in air as 330 m s^(-1))

Answer»

SOLUTION :(i) `V = (2d)/(t)`
(ii) Apply the FORMULA d = Vt for both the cliffs.
Then add the TWO distances to get the DISTANCE between the two cliffs.
(III) 1650 or 1.65 km .


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