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A man travels a distance of 1.5 m towards East, then 2.0 m towards South and finally 4.5 m towards north. (i) Calculate the total distance travelled. (ii) Calculate the resultant displacement. |
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Answer» Solution :The man STARTS from A and travels `1.5 m` towards EAST and reaches point B. For B 2m towards SOUTH reaches point C. From `C 4.5 m` towards north and teaches point D. Total distance travelled `= AB + BC +CD` `= (1.5 + 2 + 4.5) m = 8m ` The resultant displacement is AD. In right angled `Delta ABD, AB = 1.5 m.` `BD=DC - BC = (4.5 -2) = 2.5 m.` By Pythogoras. theorem, `AD ^(2) = AB^(2) + BD^(2)` ` = (1.5) ^(2) + (2.5) ^(2) = 2.25 + 6.25 = 8.50` ` THEREFORE AD = sqrt (8.50) ~~2.92 m` (i) Total distance travelled `= 8m.` (II) The resultant displacement `= 2.92 m.`
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