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A man whose mass is 90 kg stands on his feet on a floor. The total area of contact of his two feet with the floor is 0.036 m^(2) ("Take," g= 10 ms^(-2)).How much is the pressure exerted by him on the floor? |
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Answer» Solution : The weight of the man (thrust), `F = MG = 90 kg xx 10ms^(-2) = 900 N` Pressure, ` P = F/A = (900 N)/(0.036 m^(2)) = 25000 ` PA |
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