1.

A mass of 5 kg is moving along a circular path of radius 1 m. If the mass moves with 300 rev/min. its's kinetic energy would be

Answer»

`250pi^(2)`
`100 pi^(2)`
`5 pi^(2)`
`0`

Solution :`V=omegaR,OMEGA=(2PI)/T=10 pi "rod"//s`
`V=10 pi ms^(-1)impliesK.E=1/2 mv^(2)=250pi^(2)J`


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