1.

A mechanic can open a nut by applying a force of 150N while using a lever handle of length 40cm. How long a handle is required if he wants to open it by applying a force of only 50 N?

Answer»

Solution :In the first case, F=150N r=40cm =0.4m
The moment of FORCE needed to open the nut
`=150N times 0.4N=60 Nm`…….(i)
In the second case, F=50N
If he uses the handle the length Lm, then
Moment of force `=50N times L m =50 L N m`………(II)
From EQNS. (i) and (ii)
`50L=60`
or `L=60/50=1.2 m`


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