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A mixture of `0.1 mol ` of `Na_(2)O` and `0.1 mol ` of `BaO` is dissolved in `1000 g` of `H_(2)O`. Calculate the vapour pressure of solution at `373 K`. |
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Answer» `Na_(2)O` and `BaO` both are ionic compounds and are completely ionized to give `3` and `2 ions`, respectively, `(i) Na_(2)O rarr 2Na^(o+) O^(2)-(i=3)` `(ii)BaO rarr Ba^(2+) + O^(2-) (i=2)` `:.(P^(@)-P_(s))/P^(@) = ichi_(Na_(2)O) + ichi_(BaO)` `(760-P_(s))/(760) =3xx(0.1)/(0.1+0.1+55.5)+2xx (0.1)/(0.1+0.1+55.5)` `:.P_(s)=753.21 mm Hg` Alternatively Total number of ions=`5xx0.1=0.5` `(P^(@)-P_(s))/P^(s) =n_(2)/n_(1) =0.5/55.5 =0.009` `760-P_(s)/P_(s)=0.009` Solve for `P_(s) rArr 753.21 mm Hg`. |
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