A mixture of ethylene and excess of `H_2` has a pressure of 600 mm Hg. The mixture was passed over nickel catalyst to convert ethylene to ethane. The pressure of the resultant mixture at the similar condition of temperature and volume dropped to 400 mm Hg. the fraction of `C_2H_4` by volume dropped to 400 mm Hg. The fraction of `C_2H_4` by volume in the original mixture is:A. 1/3rd of the total volumeB. 1/4th of the total volumeC. 2/3rd of the total volumeD. 1/2 of the total volume

A mixture of ethylene and excess of `H_2` has a pressure of 600 mm Hg.

1.	A mixture of ethylene and excess of `H_2` has a pressure of 600 mm Hg. The mixture was passed over nickel catalyst to convert ethylene to ethane. The pressure of the resultant mixture at the similar condition of temperature and volume dropped to 400 mm Hg. the fraction of `C_2H_4` by volume dropped to 400 mm Hg. The fraction of `C_2H_4` by volume in the original mixture is:A. 1/3rd of the total volumeB. 1/4th of the total volumeC. 2/3rd of the total volumeD. 1/2 of the total volume
Answer» Correct Answer - A Let `n` mol of `(C_2H_4+H_2)` and `x` mol of `C_2H_4` `H_2=(n-x)mol` `underset(x)(C_2H_4)+underset(x)(H_2)rarrunderset(x mol)(C_2H_4)` After reaction `(C_2H_6+H_2` left) `x+n-x-x=n-x` [Total `H_2=(n-x),H_2` reacted `=x]` `H_2` left `=(n-x-x)` `n=600,n-x=400` `(n)/(n-x)=(600)/(400)` `x=(n)/(3)` volume of `C_2H_4` `=(1)/(3)` rd of total volume