1.

A monatomic gas at a pressure P, having a volume V expands isothermally to a volume 2 V and then adiabatically to a volume 16 V. The final pressure of the gas is ( take gamma=5/3)

Answer»

<P>64 P
32 P
P/64
16 P

Solution :If `P_2`is pressure after ISOTHERMAL expansion, then
`P_2V_2=P_1V_1 , P_2=P_1V_1/V_2=PxxV/(2V)=P/2 `
If P3 is pressure after ADIABATIC expansion, then
`P_2V_2^(gamma)=P_3V_3^(gamma)`
`P_3=P_2 (V_2/V_3)^gamma=P/2((2V)/16)^(5//3) = P/2 (1/8)^(5//3)`
`=P/2(1/2^3)^(5//3) =P/2xx1/2^5 =P/64`


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