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A Monkey Climbs Up A Greased Pole, Ascends 20m And Slip 4m In Alternate Minutes. If The Pole Is 96m High, How Many Minutes Will It Take To Reach The Top? |
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Answer» net HEIGHT climbed in 2 min = 20m - 4M = 16M In 10 min the net height climbed = 16 * 10/2 = 80m Remaining height = 96M - 80m = 16m In the 11th min , the monkey will be ascending up. Time TAKEN to ascend the last 16min 16/20 = 4/5min Total time taken = 10 + 4/5 = 54/5 min. net height climbed in 2 min = 20m - 4m = 16m In 10 min the net height climbed = 16 * 10/2 = 80m Remaining height = 96m - 80m = 16m In the 11th min , the monkey will be ascending up. Time taken to ascend the last 16min 16/20 = 4/5min Total time taken = 10 + 4/5 = 54/5 min. |
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