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K Is 50% Faster Than L. If L Starts At 9 A.m. And K Starts At 10 A.m. L Travels At A Speed Of 50 Km/hr. If L And K Are 300 Kms Apart, The Time When They Meet When They Travel In Opposite Direction Is ? |
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Answer» let 't' be the time after which they met since L starts. 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs PAST the time that L starts So they meet at (9 + 3)hrs = 12:00 noon. let 't' be the time after which they met since L starts. Given K is 50% faster than L 50 t + 1.5*50(t-1) = 300 50 t +75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that L starts So they meet at (9 + 3)hrs = 12:00 noon. |
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